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Help defeat the bug of the Chinese module.

Help defeat the bug of the Chinese module.


I welcome everyone. I bought something like that from the Chinese, such modules.



The modules are not bad, in terms of the function I need, but that is not the problem. The problem is one big flaw, namely. There is a button on the back of the board.





When you press this button, when the device is turned on, the display backlight turns on and off. But the trouble is that when the power is turned on, the display backlight is turned off by default, and you need to turn it on, which is very interesting, with this button, which is located on the back of the module and after installation there is no access to it. And when you turn off the power, the selection is reset, and the next time you turn on the display again without backlight. I don’t want to consider the option of displaying a button on the panel, I’m planning to do everything minimalistly, but I need the display to be highlighted when the device is turned on. The option with shortening the button is not suitable, if you hold it pressed while power is applied, the module switches to the setting mode. The LED that illuminates the display does not come out directly, the module starts to behave inappropriately. How to solve this in the simplest and most energy-efficient way? The module is supposed to be used in a portable device, I do not want to spend extra costs (but the display should be highlighted).
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9 comments
Author
Thank you sincerely for the advice, but it was worth reading the comments above. I myself suggested this, and a solution has already been found dance2
I did not check the input voltage, if there is 30 volts, then the resistor is better at least 1500 Ohms
The backlight is an LED.You need to connect it directly to power. Connect in series with a current limiting resistor.

The photo is not very detailed, it seems his conclusions on the first photo from the right from the end.
The easiest option. Just unsolder both and apply voltage from the device input through a resistor.

300-5000 ohms choose acceptable brightness
Author
However, it worked) That's what all ingenious simply means) True, if you turn off the power and turn it on again, nothing happens, but this is understandable, the Conder needs to be discharged. Plans to turn on / off every minute and is not included, but for the sake of experiment I’ll try to put a smaller capacity.
In parallel with the button, connect a 47 uF x 25 V. capacitor (voltage needs to be clarified). I did this with the tablet as a TV set-top box, when I applied power to the circuit, the tablet turned on itself ... You may have to pick up a capacitor ...

Source https://www.youtube.com/watch?v=fHJ94sw3tiw
Author
Structurally, the LED and the display are one. Well, more precisely, under the display there is this illuminating "substrate", in which the LED is mounted. On the one hand, the “substrate” face is completely blocked by the LED, on the other two - on the display legs, on the third is open, in principle, as an option, you can try. But what does it mean, the morning of the evening is wiser. The LED conclusions are in principle accessible, I will try to gently solder them from the board and power them directly, and if the controller starts to go crazy where the LED went, I solder to the other pads, it will always be turned off anyway.
The LED that illuminates the display does not come out directly, the module starts to behave inappropriately.
How did you do this?
Directly power the LED, backlight display
Have you considered the option of an independent, additional backlight LED?
Connect in parallel to the button the output of a single-shot, which starts when power is applied. The actual implementation depends on how the button is enabled.

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