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LED lamp based on the finished module



A few years ago I bribed non-eBay, ready-made LED modules (how good they are: they cost about 35 rubles / pc; an almost finished lamp, just insert into the case): why not use them? At the dacha, I did not throw anything away (such a “plushkin”!) And I had a lot of such lamps.

The LED module is a rectangular plate - 42x42 mm with 12 LEDs type 5630-0.5 soldered on it, connected in series.

It is made of fiberglass. On the front side of the SMD components - there is a diode bridge and resistors. On the reverse side there is a metal film capacitor (which sets the current through the LEDs) and electrolytic (for smoothing the ripple.

The circuit diagram (approximate) is presented on figure.

If we calculate the current flowing through the LEDs according to the formula I = (C1 * (U-U₁)) / 3.18, where I is the current in mA; C1 = 1.5 μF; U = 220 V; U₁ is the voltage drop across the LEDs (3 V x 12 = 36 V), then we get 87 mA. If the maximum current through the 5630-0.5 LEDs is 150 mA, then at this cooling current the module is not required.

Energy-saving light bulb assembled on snaps

and understands very simply. It is only necessary to be extremely careful so as not to damage the flask (in the flask, the poisonous substance is mercury, and it must be disposed of).


then to insert a "glass" (since the lamp has no galvanic isolation). Then he milled a landing for a future board.

In order to protect against electric shock, a “glass” was cut out (from the packaging from the headphones)

and pasted it inside with superglue glue.

The LED module was first cut with scissors for metal, and then fitted "tightly" with a file.

Soldered to the cap - everything, the work is finished.

So in half an hour you can assemble a fairly solid LED lamp. The lamp almost does not heat up (after an hour of work in the table lamp it’s barely warm). According to calculations, the lamp should give out about 3 watts, but in fact - 4-5 watts (due to the thermal temperature of 4200 K). It costs in stores about 120-130 rubles. (Now, probably, more expensive). The lamp turned out to be quite tight, so it can be used outdoors (by the way, I use it on the porch cottages).

Note. I replaced the capacitor with 50μFx100V. He just exploded in me. Indeed, capacitors must be rated for a voltage of 2 times the peak voltage.
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9 comments
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ino53,
Remark on the case accepted.
I’ll tell you which (channels) sites you need to watch
Dr. Dew, for example.
2Dem
gives three watts of light
My comment at 16:56 was considered by the site to be a flood, and after repeating the comment at 17:02, I posted both! I wanted to convey that the power in Watts is the power consumed by the LED from the power source: P = U * I. An LED emits a luminous flux expressed not in watts, but in lumens! Tentatively: the efficiency of an incandescent lamp is 10-12 lm / W, luminescent - 35-40 lm / W, LED - 130-140 lm / W. yes
Well, as if I hadn’t scientifically written here, in the sense that if an LED gives three watts of light, then these are exactly three watts, and not more;)
2Dem
If the LEDs give three watts, then they give three watts
Yes, they do not give, but they consume! yes
2Dem
If the LEDs give three watts, then they give three watts
It seems more correct they do not give, but consume! yes
2DemI was waiting for the color temperature bazaar to go ...
According to calculations, the lamp should give out about 3 watts, but in fact - 4-5 watts (due to the thermal temperature of 4200 K).

Here my brain exploded))) If the LEDs give three watts, then they give three watts. And thanks to the color temperature, 4200K will visually appear to be 2-2.5 watts, since in suites with the same power 6500 is brighter than 4200.
With R2, something is wrong - at a current of 87 mA on k51 it falls ... lazy to count for 2 watts.

AND, MAXI.MUS, no offense, draw the scheme more accurately, the absence of points of the eye hurts.

We advise you to read:

Hand it for the smartphone ...