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To heat a steel nail with electric current - is it possible and with what?

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This is what I am doing from old nails. Antique pens for of furniturehangers and so on. All this business is heated on coals. But is it possible to heat a steel nail 3-4 mm thick with red-hot current? I tried welding, but it apparently goes into defense, 250A is not enough. I probably need some kind of resistor.
Or can make what type of transformer for "quick soldering iron"?
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24 commentary
+1
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Relative voltage drop. on a trance - delta Ut = 0.12 at Jav. ~ 4 A / mm2
This is all at a current of 5 ... 10A. What will happen there at a current of 200A ??
I know from experience - ordinary weak trance (50Hz) will not give any transformation 400/1 (loss in iron). And the flux linkage is bad.
In a normal lowering trance with a short circuit of the secondary winding, it does not burn. Because U falls on the iron.
+1
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Quote: Pronin
at the output (secondary) ~ 2 ... 3v

On the nail you need 0.5 V.
+1
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Dmitrij,
You can make Chinese bells, then those that are small, bigger, even bigger. And if immediately after heating immerse in oil, then harden more
Author +1
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well, it will already be a unified product ... And so unique, "ancient" ...))

By the way, the metal after forging becomes so interesting, very durable and sonorous.
+1
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I don’t want to call the store, well, believe me they are in big household markets, I bought it once, I wanted to stir up something with it (Archimedes mini pump))
Author +1
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The nail is ordinary, I make it square with a hammer, then I twist it, I will bend ...

Screw interesting idea, but where to get them big? It’s rare for us. In the internet is it worth a look.

I looked, cheto did not like the shape, and the screw there is not the whole.
+1
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And where you take square nails, you can see those about which the Bible says. The store has screw nails, do not want ready-made? They are for twisting when driving into a tree.
I hope comrades took into account that the nail is square in calculating its resistance and heat transfer to air?
+1
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Indeed, 0 didn’t add there and R-nail ~ 0.0013
But, additional Rdob still need 0.13 ... 0.15ohm at 200 A
Efficiency will, of course, be none (very low). The entire power of the inverter (4 kW) is consumed by the auxiliary. And it is desirable that Robit also warms up the desired Nail as well. And then the warm-up time ~ 100 sec
And with a low-power trans (50Hz) a large current> 100A is unlikely to be obtained. In a real trance, the resistance (U sags) and the efficiency is low. Take> 300 watts, at the output (secondary) ~ 2 ... 3v
Author +1
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Ivan_Pokhmelev,
you see, what topic is interesting, and you "count, count ..."
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Recalculated taking into account the temperature coefficient of resistance. It turns out better there. The coefficients for steel in different sources are different, from 0.003 to 0.006, apparently for different grades. With an average of 0.005, it turns out that the resistance increases from 0.001 to 0.006 Ohms. Then in 2 minutes you can warm up to 900 degrees with a current of 130 A, the power on the nail is about 60 watts.
But the devil, as always, is in the details.)) How to ensure a low transition resistance at the points of contact with the nail, given the deterioration of the joints during heating? Plus heat dissipation to the contacts. The melting point of copper is 1080, so the contacts must be made of steel (or titaniumyes), and this is a large transition resistance. That's where the ambush is!
Author +1
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Yes, the welder probably will not withstand this mode. It is necessary to stir up the transformer.
+1
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Power in this case (in the nail itself, without loss of supply) is ridiculous - only fifty watts. So you can use a regular trans-watt at 100-150, but with an awesomely thick secondary.
+2
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Quote: Pronin
rated R nail ~ 0.13ohm (d = 3.5mm L = 100mm)

Let me disagree. R nail with the indicated parameters is approximately 0.0013 ohms.
I took d = 4 mm and 800 degrees for the calculation, but this is not essential for estimating the order of values.
Taking into account the achievement of the heat balance in this case (d = 4 mm, the mass of the nail is about 10 g, the temperature is 900) Q = 6700 J. If you heat for 8 s, then the current needs 700 A. To reduce the current to 200 A, you need to heat for 3 minutes.
The heat transfer coefficient was 20.
+2
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Here the admin does not allow adding (editors), so briefly:
It is necessary to reduce the voltage at the output of the welder. Or add Rdob.
This may be your extra nail (genuine). Rdob. put into wire break (brass, copper). The ends of this Rdob. flattened and clamp. You can contact the sample with a non-consumable electrode (or bolt connection). At the point of contact you need the least resistance ... (clean)
You can calculate which Rdob. ~ 0.13 ... 0.15 ohm

Initially - allowable drawdown at the inverter up to ~ 25 ... 30 V
rated R nail ~ 0.13ohm (d = 3.5mm L = 100mm)
Sk.nado Q for heating the nail (m = 12g) to T ~ 900g. -> 5500 ... 6000 J
Q = I2 * R * t (current 100 ... 150A) -> 6 ... 8 sec.

In a vise, the end of the nail is undesirable, because heat will be sucked out. It is necessary through an adapter some thread.
Author 0
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It’s convenient with the current, set it in a vice, threw the terminal and then turn it wherever you want
+2
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What, too lazy to consider? And what does "red" mean?
If we take "red-hot" - 800 degrees Celsius, then a 100 mm nail must be heated to this temperature with a current of 220 A for 2 minutes. The voltage on the nail will be 0.2 V.
Calculation is roughly rough. ;)
+2
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I remember you once did a hydrogen generator, modified it? So ignite the hydrogen burner, and heat that stubborn nail to red))
Author +1
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Well, this is what I have and do not need to stir up anything
+1
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Why did you decide to use electric current, in this case, heat welding, there are many other ways: induction, blacksmithing (with bellows), burning hydrogen, an electric furnace, gas
+3
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If there is an extra, which is not a pity .... smiles
+2
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It is necessary to reduce the voltage at the output of the welder. Or add Rdob.
+2
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Theoretically, a microwave can be tried.
Author +1
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do not bother with similar comments
+1
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First, evaluate the required current value. Physics textbook - to help. ;)

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